6-Machine Learning (QBoost) with Quantum Annealing#

Open in Colab

In this section, we describe an application of machine learning (ML) with quantum annealing (QA) optimization.

In the first, we show application for clustering task using JijModeling and OpenJij.
In the second, we execute an ensemble study called QBoost with PyQUBO and D-Wave sampler.


Clustering is the task of dividing given set of data into nn clusters (nn is our input). For the sake of simplicity, let us consider the number of cluster nn is 2 in this time.

Clustering Hamiltonian#

We demonstrate clustering by minimizing the following Hamiltonians.

H=i,j12di,j(1σiσj) H = - \sum_{i, j} \frac{1}{2}d_{i,j} (1 - \sigma _i \sigma_j)

Where i,ji, j is sample No., di,jd_{i, j} is a distance between ii and jj, σi={1,1}\sigma_i=\{-1,1\} is spin variable that indicates whether ii belong to one of the two clusters.

Each term of this Hamiltonian sum behaves as follows.

  • 0 for σi=σj\sigma_i = \sigma_j

  • di,jd_{i,j} for σiσj\sigma_i \neq \sigma_j

Note that minus of R.H.S., Hamiltonian means the problem is “Choosing pairs of {σ1,σ2}\{\sigma _1, \sigma _2 \ldots \} that maximizes the distance between the samples of different classes”.

Importing the required libraries#

We import several libraries for clustering.

# import libraries
import numpy as np
from matplotlib import pyplot as plt
import pandas as pd
from scipy.spatial import distance_matrix

import openjij as oj
import jijmodeling as jm
from jijmodeling.transpiler.pyqubo.to_pyqubo import to_pyqubo

Clustering with JijModeling and OpenJij#

At first, we formulate the mathematical model in JijModeling. We cannot use spin variable in JijModeling, so we change spin variable σi\sigma_i to binary variable xix_i by using the relationship σi=2xi1\sigma_i = 2x_i - 1.

problem = jm.Problem("clustering")
d = jm.Placeholder("d", dim=2)
N = d.shape[0]
x = jm.Binary("x", shape=(N))
i = jm.Element("i", (0, N))
j = jm.Element("j", (0, N))
problem += (
    -1 / 2 * jm.Sum([i, j], d[i, j] * (1 - (2 * x[i] - 1) * (2 * x[j] - 1)))
Problem: clusteringmin(0.5)i=0dshape(0)1j=0dshape(0)1di,j(1(2xi1)(2xj1))xi0{0,1}\begin{alignat*}{4}\text{Problem} & \text{: clustering} \\\min & \quad \left( -0.5 \right) \cdot \sum_{ i = 0 }^{ d_{\mathrm{shape}(0)} - 1 } \sum_{ j = 0 }^{ d_{\mathrm{shape}(0)} - 1 } d_{i,j} \cdot \left( 1 - \left( 2 \cdot x_{i} - 1 \right) \cdot \left( 2 \cdot x_{j} - 1 \right) \right) \\& x_{i_{0}} \in \{0, 1\}\end{alignat*}

Make artificial data#

Next, we create instance data for the clustering problem.

In this case, let us generate linearly separable data in a two-dimensional plane artificially. Our clustering algorithm is unsupervised learning algorithm, so we do not need to prepare answer data.

data = []
label = []
N = 100
for i in range(N):
    # generate 0 to 1 random number
    p = np.random.uniform(0, 1)
    # set class 1 when certain condition are met, and -1 when it are not met
    cls = 1 if p > 0.5 else -1
    # create random numbers following a normal distribution
    data.append(np.random.normal(0, 0.5, 2) + np.array([cls, cls]))
# formatted as a DataFrame
df1 = pd.DataFrame(data, columns=["x", "y"], index=range(len(data)))
df1["label"] = label

Let us see the data of the clustering problem.

# visualize dataset
df1.plot(kind="scatter", x="x", y="y")
instance_data = {"d": distance_matrix(df1, df1)}

Solving the clustering problem by using OpenJij#

We create mathematical model and instance data, so let us solve the clustering problem by using openjij.

pyq_obj, pyq_cache = to_pyqubo(problem, instance_data, {})
qubo, constant = pyq_obj.compile().to_qubo()
sampler = oj.SASampler()
response = sampler.sample_qubo(qubo)
result = pyq_cache.decode(response)
for idx in range(0, N):
    if idx in result.record.solution["x"][0][0][0]:
        plt.scatter(df1.loc[idx]["x"], df1.loc[idx]["y"], color="b")
        plt.scatter(df1.loc[idx]["x"], df1.loc[idx]["y"], color="r")

We can see the data is clearly separated by blue and red class.


QBoost is a one of the ensemble learning using QA. Ensemble learning involves preparing a number of weak predictors and combining the results of each of these predictors to obtain the final prediction result.

QBoost uses QA to optimize the best combination of learners for a given training data. We handle classification problem in this time.

We define that the set of DD training data are {x(d)}(d=1,...,D)\{\vec x^{(d)}\}(d=1, ..., D), corresponding label are {y(d)}(d=1,...,D),y(d){1,1}\{y^{(d)}\}(d=1, ..., D), y^{(d)}\in \{-1, 1\} and the (function) set of NN weak learner is {Ci}(i=1,...,N)\{C_i\}(i=1, ..., N). For some data x(d)\vec x^{(d)}, Ci(x(d)){1,1}C_i(\vec x^{(d)})\in \{-1, 1\}.

Based on the definitions above, the classification labels are as follows.

sgn(i=1NwiCi(x(d))){\rm sgn}\left( \sum_{i=1}^{N} w_i C_i({\vec x}^{(d)})\right)

Where wi{0,1}(i=1,...,N)w_i\in\{0, 1\} (i=1, ..., N), is a weight of each predictor (bool value to adopt or not adopt the predictor for the final prediction).QBoost optimizes the combination of wiw_i so that prediction matches the training data while erasing the number of weak learners.

Hamiltonian in this problem is as follows.

H(w)=d=1D(1Ni=1NwiCi(x(d))y(d))2+λiNwiH(\vec w) = \sum_{d=1}^{D} \left( \frac{1}{N}\sum_{i=1}^{N} w_i C_i(\vec x^{(d)})-y^{(d)} \right)^2 + \lambda \sum _i^N w_i

The first term represents the difference between weak classifier and the correct label. The second term represents a degree of the number of weak classifier to be employed in the final classifier. λ\lambda is the regularization parameter that adjust how much the number of weak classifiers affects the total Hamiltonian.

We optimize this Hamiltonian by recognizing the first term as a cost (objective function) and the second term as a constraint.Minimizing with QA allows us to obtain a combination of weak classifiers that best fits the training data.

Preparation of dataset#

Let us try QBoost. We use the cancer identification dataset from scikit-learn for training data. For simplicity, we will only use two character types for training: “0” and “1”.

# import libraries
import pandas as pd
from scipy import stats
from sklearn import datasets
from sklearn import metrics
# load data
cancerdata = datasets.load_breast_cancer()
# set the number of training data & test data
num_train = 450

In this time, we consider that feature of noise exists.

data_noisy = np.concatenate(
    (cancerdata.data, np.random.rand(cancerdata.data.shape[0], 30)), axis=1
(569, 60)
# convert from label {0, 1} to {-1, 1}
labels = (cancerdata.target - 0.5) * 2
# divide dataset to training and test
X_train = data_noisy[:num_train, :]
X_test = data_noisy[num_train:, :]
y_train = labels[:num_train]
y_test = labels[num_train:]
# from the result of weak learnor
def aggre_mean(Y_list):
    return ((np.mean(Y_list, axis=0) > 0) - 0.5) * 2

Creating Set of Weak Learner#

We make weak learner with scikit-learn. In this time, we choose decision stump. Decision stump is a single-layer decision tree. As it will be used as a weak classifier, the features to be used for segmentation are selected randomly (it’s a good understanding that we execute single-layer of random forest).

# import required libraries
from sklearn.tree import DecisionTreeClassifier as DTC

# set the number of weak classifier
num_clf = 32
# set the number of ensembles to be taken out for one sample in bootstrap sampling
sample_train = 40
# set model
models = [DTC(splitter="random", max_depth=1) for i in range(num_clf)]
for model in models:
    # extract randomly
    train_idx = np.random.choice(np.arange(X_train.shape[0]), sample_train)
    # make decision tree with variables
    model.fit(X=X_train[train_idx], y=y_train[train_idx])
y_pred_list_train = []
for model in models:
    # execute prediction with model
y_pred_list_train = np.asanyarray(y_pred_list_train)
y_pred_train = np.sign(y_pred_list_train)

We look accuracy of all weak learner as the final classifier. Henceforth, we refer to this combination as baseline.

y_pred_list_test = []
for model in models:
    # execute with test data

y_pred_list_test = np.array(y_pred_list_test)
y_pred_test = np.sign(np.sum(y_pred_list_test, axis=0))
# compute score of prediction accuracy
acc_test_base = metrics.accuracy_score(y_true=y_test, y_pred=y_pred_test)

Execute QBoost with OpenJij#

Let us creater QBoost model.

# set class of QBoost
class QBoost:
    def __init__(self, y_train, ys_pred):
        self.instance_data = {"y": y_train, "C": ys_pred}
        self.pyq_obj, self.pyq_cache = to_pyqubo(
            self.problem, self.instance_data, {}

    def qboost_Hamiltonian(self):
        problem = jm.Problem("QBoost")
        C = jm.Placeholder("C", dim=2)
        y = jm.Placeholder("y", dim=1)
        N = C.shape[0].set_latex("N")
        D = C.shape[1].set_latex("D")
        w = jm.Binary("w", shape=(N))
        i = jm.Element("i", (0, N))
        d = jm.Element("d", (0, D))
        obj = jm.Sum(
            (1 / N * jm.Sum(i, w[i] * C[i, d]) - y[d])
            * (1 / N * jm.Sum(i, w[i] * C[i, d]) - y[d]),
        constraint = jm.Constraint("constraint", jm.Sum(i, w[i]))
        problem += obj
        problem += constraint
        self.problem = problem

    def sampling(self, qubo, **kwargs):
        sampler = oj.SASampler(**kwargs)
        response = sampler.sample_qubo(qubo)
        return response

    def decode(self, response):
        return self.pyq_cache.decode(response)

    # set function for converting to QUBO
    def to_qubo(self, norm_param=1):
        # set value of hyperparameter
        self.multiplier = {"constraint": norm_param}
        model = self.pyq_obj.compile()
        return model.to_qubo(feed_dict=self.multiplier)
qboost = QBoost(y_train=y_train, ys_pred=y_pred_list_train)
Problem: QBoostmind=0D1(1Ni=0N1wiCi,dyd)(1Ni=0N1wiCi,dyd)s.t.constraint:i=0N1wi=0,wi0{0,1}\begin{alignat*}{4}\text{Problem} & \text{: QBoost} \\\min & \quad \sum_{ d = 0 }^{ D - 1 } \left( \frac{ 1 }{ N } \cdot \sum_{ i = 0 }^{ N - 1 } w_{i} \cdot C_{i,d} - y_{d} \right) \cdot \left( \frac{ 1 }{ N } \cdot \sum_{ i = 0 }^{ N - 1 } w_{i} \cdot C_{i,d} - y_{d} \right) \\\text{s.t.} & \\& \text{constraint} :\\ &\quad \quad \sum_{ i = 0 }^{ N - 1 } w_{i} = 0,\\[8pt]& w_{i_{0}} \in \{0, 1\}\end{alignat*}
# make QUBO with lambda=3
qubo = qboost.to_qubo(1)[0]
response = qboost.sampling(qubo, num_reads=100, num_sweeps=10)
result = qboost.decode(response)

Let us check the accuracy in the training/validation data when using a combination of weak classifiers obtained by D-Wave.

accs_train_Dwaves = []
accs_test_Dwaves = []

for solution in result.record.solution["w"]:
    idx_clf_DWave = solution[0][0]
    y_pred_train_DWave = np.sign(
        np.sum(y_pred_list_train[idx_clf_DWave, :], axis=0)
    y_pred_test_DWave = np.sign(
        np.sum(y_pred_list_test[idx_clf_DWave, :], axis=0)
    acc_train_DWave = metrics.accuracy_score(
        y_true=y_train, y_pred=y_pred_train_DWave
    acc_test_DWave = metrics.accuracy_score(
        y_true=y_test, y_pred=y_pred_test_DWave
energies = result.evaluation.energy

We make a graph with energy on the horizontal axis and accuracy on the vertical axis.

plt.figure(figsize=(12, 8))
plt.scatter(energies, accs_train_Dwaves, label="train")
plt.scatter(energies, accs_test_Dwaves, label="test")
plt.title("relationship between energy and accuracy")
print("base accuracy is {}".format(acc_test_base))
print("max accuracy of QBoost is {}".format(max(accs_test_Dwaves)))
    "average accuracy of QBoost is {}".format(
base accuracy is 0.9495798319327731
max accuracy of QBoost is 0.9663865546218487
average accuracy of QBoost is 0.9247058823529412